Code:
#include <iostream>
#include <iomanip>
int main()
{
using namespace std;
int expected [] = {604,604,604,605,606,606,606,607,608,608,608,609,610,610,610,611,612,612,612,613,614,614,614,615,616,616,616,617,618,618,618,619,620,620,620,621,622,622,622,623,624,624,624,625,626,626,626,627,628,628,628,629,630,630,630,631,632,632,632,633,634,634,634,635,636,636,636,637,638,638,638,639,640,640,640,641,642,642,642,643,644,644,644,645,646,646,646,647,648,648,648,649,650,650,650,651,652,652,652,653,654,654,654,655,656,656,656,657,658,658,658,659,660,660,660,661,662,662,662,663,664,664,664,665,666,666,666,667,668,668,668,669,670,670,670,671,672,672,672,673,674,674,674,675,676,676,676,677,678,678,678,679,680,680,680,681,682,682,682,683,684,684,684,685,686,686,686,687,688,688,688,689,690,690,690,691,692,692,692,693,694,694,694,695,696,696,696,697,698,698,698,699,700,700,700,701,702,702,702,703,704,704,704,705,706,706,706,707,708,708,708,709,710,710,710,711,712,712,712,713,714,714,714,715,716,716,716,717,718,718,718,719,720,720,720,721,722,722,722,723,724,724,724,725,726,726 };
for(int i=7;i<252;i++) {
float mana = (i/2.0)+600;
cout << setprecision(3) << "For INT = " << i << ", Mana is " << mana << ", Expected value is " << expected[(i-7)] << ", Actual value is " << setprecision(4) << mana << endl;
}
}
and an image of the first 31 outputs where Mana is the calculated result, Expected is your data, and Actual is the same calculated result without limiting the precision. 
Enchantress' Attributes Guide (Table Format)
Originally Posted by Eleanor
(60 again?) After that it should again increase around 311 but the max INT you can get with the current gear is 300 and it is still 6 at 300 INT. 
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